Assume that we have a generalized, time-limited pulse centered at t = 0 as shown below.
The Fourier Transform of this pulse can be developed by starting with a periodic version of this pulse where the original pulse now repeats every T seconds.
Note:
fT(t) is periodic with period T so we can express it by its exponential Fourier series as
where
and
Now let’s make a small change in notation
1. wn = n*w0
2. F(wn) = T*Fn
We now have
and
The sum can be rewritten as
or
Taking the limit as T ¥
But w0 = 2p/T so for large T let w0 Dw and the limit becomes
or since T ¥ implies that Dw 0 and the sum, in the limit, becomes an integral
and
This pair of equations defines the Fourier Transform
1. F(w) is the Fourier Transform of f(t)
2. f(t) is the inverse Fourier Transform of F(w)
3. F(w) is also called the Spectral Density of f(t) as it describes how the energy of the original pulse is distributed as a function of frequency (in radians per second)
I use a backwards upper case script “F” to denote taking the Fourier Transform of a function and the same symbol with a “-1” superscript to denote taking the inverse Fourier Transform.
Take the Fourier Transform of the single-sided exponential
Note that the Fourier Transform is complex. It has a magnitude and a phase. The magnitude is found by multiplying it by its complex conjugate and taking the square root.
This is the magnitude
Now find the phase. First, find the real and imaginary parts.
Therefore the real part is
and the imaginary part is
The phase is then given by
We run into special functions
when taking the Fourier Transform of functions that have infinite energy. The first of these special functions is the Delta Function
Where Ge(t) is any function from the set of all functions having the properties
1.
2. For all t ¹ 0
Integrating the product of the Delta Function with a “well-behaved” function results in “sampling” the “well-behaved” function at the time that the Delta Function goes to infinity. Or
Proof
Use Integration by parts
Let U(t) = f(t) and dV(t) = d(t-t0)dt
Case 1: a < t0 < b
Q.E.D
Case 2: t0 < a or t0 > b
Q.E.D
Take the Fourier Transform of a constant
Here the integral can’t be directly computed, we have to approach it as a limiting case. Let’s replace the constant with a parameterized function that equals the constant as its parameter approaches zero, the double-sided exponential function:
Now the Transform becomes:
Let u = -w in the first integral
From our first example this is:
Now we need to take the limit as a 0 to get F(w)
so this is a d-function that goes to ¥ at w = 0 if its integral is a constant.
Let a*x = w
Therefore
1: Find the Fourier Transforms for each of the two pulses
2: Find the transfer function for the simple RC low-pass filter
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3: Determine the Fourier Transform of the RC low-pass filter output due to each of the pulses in part 1
4: Find the limit of each of the results in part 3 as Dt 0
If f(t) F(w)
Then F(t) 2p f(-w)
Proof:
Therefore
Let u = w and v = t
Now let w = v and t = u
Therefore F(t) 2p f(-w)
And if f(t) is an even function
F(t) 2p f(w)
If f1(t) F1(w)
And f2(t) F2(w)
Then [a*f1(t) + b*f1(t)] [a*F1(w) + b*F2(w)]
Proof:
Results due to the linearity of integration
If f(t) F(w)
Then for a real
f(a*t)
Proof:
case 1: a > 0 Let x = a*t
or
case 2: a < 0 Again let x = a*t
(Note the limits are now backwards)
or
Therefore including both cases
f(a*t)
Q. E. D.
Note: The compression of a function in the time domain results in an expansion in the frequency domain and vice versa.
If
Then
Proof:
or
Q. E. D.
Note: The Modulation Theorem (very important in communications)
Remember Euler’s Identities
and
therefore
or
similarly
or
If
Then
Proof:
Q. E. D.
If
Then
And
Proof:
First for differentiation (part 1)
or
Q.
E. D. for part 1
Now for integration (part 2)
Interchanging the order of integration
or
Q. E. D. for part 2
If
Then
Proof:
or
Q. E. D.
Definition: the convolution of two functions is defined as:
Time Convolution
If
And
Then
Proof:
Therefore
Let u = t - t in the inner integral
Since the inner integral is no longer a function of t, it can be brought out as a constant and this leaves
or
Q. E. D
Frequency Convolution
If
And
Then
Proof: Same method
as for time convolution