Notes
Slide Show
Outline
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Chapter 7
  • Series-Parallel Circuits
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The Series-Parallel Network
  • Branch
    • Part of a circuit that can be simplified into two terminals
  • Components between these two terminals
    • Resistors, voltage sources, or other elements
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The Series-Parallel Network
  • Complex circuits
    • May be separated both series and/or parallel elements
  • Other circuits
    • Combinations which are neither series nor parallel
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The Series-Parallel Network
  • To analyze a circuit
    • Identify elements in series and elements in parallel
  • In this circuit
    • R2, R3, and R4 are in parallel
  • This parallel combination
    • Series with R1 and R5
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The Series-Parallel Network
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The Series-Parallel Network
  • In this circuit
    • R3 and R4 are in parallel
    • Combination is in series with R2
  • Entire combination is in parallel with R1
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Analysis of Series-Parallel Circuits
  • Rules for analyzing series and parallel circuits still apply
  • Same current occurs through all series elements
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Analysis of Series-Parallel Circuits
  • Same voltage occurs across all parallel elements
  • KVL and KCL apply for all circuits
    • Whether they are series, parallel, or series-parallel
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Analysis of Series-Parallel Circuits
  • Redraw complicated circuits showing the source at the left-hand side
  • Label all nodes
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Analysis of Series-Parallel Circuits
  • Develop a strategy
    • Best to begin analysis with components most distant from the source
  • Simplify recognizable combinations of components
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Analysis of Series-Parallel Circuits
  • Determine equivalent resistance RT
  • Solve for the total current
  • Label polarities of voltage drops on all components
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Analysis of Series-Parallel Circuits
  • Calculate how currents and voltages split between elements in a circuit
  • Verify your answer by taking a different approach (when feasible)
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Analysis of Series-Parallel Circuits
  • Combining R2 and R3 in parallel
    • Circuit reduces to a series circuit
    • Use Voltage Divider Rule to determine Vab and Vbc.
    • Note that Vbc = V2 is the voltage across R2 and R3
    • Calculate all currents from Ohm’s Law.
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Analysis of Series-Parallel Circuits
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Analysis of Series-Parallel Circuits
  • To find voltage Vab,
    • Redraw circuit in  simple form
  • Original circuit
    • Two parallel branches
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Analysis of Series-Parallel Circuits
  • Vab
    • Determined by combination of voltages across R1 and R2 , or R3 and R4
  • Use Voltage Divider Rule to find two voltages
  • Use KVL to find Vab
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Analysis of Series-Parallel Circuits
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Analysis of Series-Parallel Circuits
  • To find currents in the circuit
    • First redraw the circuit
    • Move source branch all the way to left
  • Reduce circuit to a series circuit
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Analysis of Series-Parallel Circuits
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Analysis of Series-Parallel Circuits
  • Voltages
    • Use Ohm’s Law or Voltage Divider Rule
  • Currents
    • Use Ohm’s Law or Current Divider Rule
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Analysis of Series-Parallel Circuits
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Bridge Circuit
  • Circuit has Rx = 15 kW
  • Determine Vab
  • Redraw circuit as shown on slide
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Bridge Circuit
  • Voltage Divider Rule
    • Determine Va and Vb.
  • Ground reference point
    • Take at bottom of circuit
  • Vab = 0.5 V
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Bridge Circuit
  • Rx is a short circuit (0 W)
  • Voltage Divider Rule
    • Determine VR1
  • VR2 = 10 V
  • Vab = 8 V
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Bridge Circuit
  • Rx is open
  • Find VR1
  • We know VR2 = 0 V
    • No current through it
  • Vab = –2 V
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Transistor Circuit
  • Transistor
    • Device that amplifies a signal
  • Operating point of a transistor circuit
    • Determined by a dc voltage source
  • We will determine some dc voltages and currents
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Transistor Circuit
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Transistor Circuit
  • Apply KVL:
  • VBB = RBIB + VBE + REIE
  • Using IE = 100IB, we find IB = 14.3 mA.
  • Other voltages and currents can be determined
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Potentiometers
  • Example of variable resistor used as potentiometer
    • Volume control on a receiver
  • Moveable terminal is at uppermost position
    • Vbc = 60 V
  • At the lowermost position
    • Vbc = 0 V
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Potentiometers
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Potentiometers
  • Vbc changes
    • If load is added to  circuit
    • At upper position
      • Vbc = 40 V
  • At the lower position
    • Vbc = 0 V